TUGAS : Pemrograman komputer IAS

Soal :

Buat program pada komputer IAS sebgai berikut :

-          Kalikan data di memori alamat 0551 dan data dimemori alamat 0552

-          Simpan hasil perkalian tersebut dimemori (MSB di alamat 0556 dan LSB dialamat 0557)

-          Jumlahkan data LSB hasil perkalian tersebut dengan isi memori 0553

-          Simpan hasil penjumlahan tersebut di alamat 0559

-          Program Counter ada dimemori 0011

1.      Buat program komputer IAS nya

2.      Gambar peta memori, perlihatkan isinya, dimana program dan data diletakkan

3.      Tulias urutan instruction cyclenya

Jawaban :

     1.      Program komputer IAS

2.   Gambar peta memori

3.   Instruction cycle

1.      Instruction cycle 1

Fetch 1 :

·         PC = 0011

·         PC → MAR

·         M(MAR) → MBR

·         MBR(20:39) → IBR

·         MBR(0:7) → IR                        : IR = LOAD to MQ

·         MBR(8:19) → MAR                 : MAR = 0551

Execute 1:

·         M(0551) → MBR                     : MBR = M(0551) = A

·         MBR → MQ                             : MQ = A

2.      Instruction cycle 2

Fetch 2 :

·         IBR (0:7) → IR                         : IR = MUL

·         IBR (8:19) → MAR                  : MAR = M(0552)

·         PC = PC + 1

Execute 2 :

·         M(0552) → MBR                     : MBR = MAR(0552) = B

·         MSB(MBR*MQ) → AC          : AC = MSB(MBR*MQ)

LSB(MBR*MQ) → MQ          : MQ = LSB(MBR*MQ)

3.      Instruction cycle 3

Fetch 3 :

·         PC → MAR                              : MAR = PC = 0012

·         M(MAR) → MBR                     : MBR = M(0012)

·         MBR(0:7) → IR                        : IR = STOR

·         MBR(8:19) → MAR                 : MAR = M(0556)

·         MBR(20:39) → IBR

Execute 3 :

·         AC → MBR                              : MBR = AC = MSB(M(0552)*MQ)

·         MBR → M(MAR)                     : M(0556) = MBR

4.      Instruction cycle 4

Fetch 4 :

·         IBR (0:7) → IR                         : IR = LOAD MQ to AC

·         PC = PC + 1

Execute 4 :

·         MQ → AC                               : AC = MQ = LSB(MQ*M(0552))

5.      Instruction cycle 5

Fetch 5 :

·         PC → MAR                              : MAR = PC = 0013

·         M(MAR) → MBR                    : MBR = M(0013)

·         MBR(0:7) → IR                        : IR = STOR

·         MBR(8:19) → MAR                 : MAR = M(0557)

·         MBR(20:39) → IBR

Execute 5 :

·         AC → MBR                              : MBR = AC = LSB(M(0552)*MQ)

·         MBR → M(MAR)                     : M(0556) = MBR

6.      Instruction cycle 6

Fetch 6 :

·         IBR (0:7) → IR                         : IR = ADD

·         IBR (8:19) → MAR                  : MAR = M(0553)

·         PC = PC + 1

Execute 6 :

·         M(0553) → MBR                    : MBR = MAR(0553) = B

·         MBR + AC → AC

7.      Instruction cycle 7

Fetch 7 :

·         PC → MAR                              : MAR = PC = 0014

·         M(MAR) → MBR                    : MBR = M(0014)

·         MBR(0:7) → IR                        : IR = STOR

·         MBR(8:19) → MAR                 : MAR = M(0559)

Execute 7 :

·         AC → MBR                              : MBR = AC

·         MBR → M(MAR)                     : M(0559) = MBR